log(2)[(2x+8)(x+4)]=5

Solution for log(2)[(2x+8)(x+4)]=5 equation:

Simplifying
log(2)[(2x + 8)(x + 4)] = 5

Reorder the terms:
glo * 2[(8 + 2x)(x + 4)] = 5

Reorder the terms:
glo * 2[(8 + 2x)(4 + x)] = 5

Multiply (8 + 2x) * (4 + x)
glo * 2[(8(4 + x) + 2x * (4 + x))] = 5
glo * 2[((4 * 8 + x * 8) + 2x * (4 + x))] = 5
glo * 2[((32 + 8x) + 2x * (4 + x))] = 5
glo * 2[(32 + 8x + (4 * 2x + x * 2x))] = 5
glo * 2[(32 + 8x + (8x + 2x2))] = 5

Combine like terms: 8x + 8x = 16x
glo * 2[(32 + 16x + 2x2)] = 5

Reorder the terms for easier multiplication:
2glo[32 + 16x + 2x2] = 5
[32 * 2glo + 16x * 2glo + 2x2 * 2glo] = 5
[64glo + 32glox + 4glox2] = 5

Solving
64glo + 32glox + 4glox2 = 5

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-5 + 64glo + 32glox + 4glox2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 64glo + 32glox + 4glox2 = 0

The solution to this equation could not be determined.